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13x^2-47x-32=0
a = 13; b = -47; c = -32;
Δ = b2-4ac
Δ = -472-4·13·(-32)
Δ = 3873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-\sqrt{3873}}{2*13}=\frac{47-\sqrt{3873}}{26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+\sqrt{3873}}{2*13}=\frac{47+\sqrt{3873}}{26} $
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